The volume of the gas at 118°c is 256.34 ml
The calculation can be done as follows
The first is to write out the parameters
(V1)First volume= 126 ml
(T1)First temperature= 58°C
(T2)second temperature= 118°C
(V2)second volume= ?
The formular is
V1/T1= V2/T2
126/58= V2/118
Cross multiply
58 ˣ V2= 126 ˣ 118
58 ˣ V2= 14868
V2= 14868/58
V2= 256.34 ML
Hence the second volume is 256.34 ml
Please see the link below for more information
https://brainly.com/question/11018966?referrer=searchResults
Answer:
149ml
Explanation:
V1/V2 = V2/T2
V2 = V1 *T2 / T1
= 126 mL * 391 K / 331 K
= 149 mL
