Examine the following table, which represents some points on a line.

x 3 0 βˆ’3 βˆ’6 βˆ’9
y βˆ’3 βˆ’2 βˆ’1 0 1
What is the equation for the line in slope-intercept form?


y=βˆ’3xβˆ’2y is equal to negative 3 x minus 2, , ,

y=3xβˆ’2y is equal to 3 x minus 2, , ,

y=βˆ’13xβˆ’2y is equal to negative 1 third x minus 2, , ,

y=βˆ’13xβˆ’6y is equal to negative 1 third x minus 6, , ,

y=βˆ’3xβˆ’6

Respuesta :

Answer:

Β  (c) Β y = βˆ’1/3x βˆ’2

Step-by-step explanation:

We notice two things in the table.

  1. y goes up by 1 when x goes down by 3.
  2. y = -2 when x = 0 (this is the y-intercept

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The slope of the line is ...

Β  m = (change in y)/(change in x) = +1/-3 = -1/3

Then the slope-intercept equation is ...

Β  y = mx +b . . . . . . slope m, y-intercept b

Β  y = -1/3x -2