Respuesta :

Answer:

30

Step-by-step explanation:

Let,

The req. number be = x

So,

Two - thirds of the number

[tex] = \frac{2}{3} x[/tex]

Then, it is reduced by 13

[tex] = \frac{2}{3} x - 13[/tex]

After that,

The req. result we get is = 7

Therefore,

By the problem,

[tex] = > \frac{2}{3} x - 13 = 7[/tex]

  • (On putting like terms on one side)

[tex] = > \frac{2}{3} x = 7 + 13[/tex]

  • (On Simplification)

[tex] = > \frac{2}{3}x = 20[/tex]

  • (On multiplying both sides with 3/2)

[tex] = > \frac{2}{3} x \times \frac{3}{2} = 20 \times \frac{3}{2} [/tex]

  • (On Simplification)

=> x = 30

Hence,

The req. number is 30.

Given that :

  • Thirteen is reduced by two-thirds of a number. And their result is 7.

To Find :

  • The number.

Solution :

Let's assume the number as x

According to the question :

[tex]\qquad \sf \: { \dashrightarrow \dfrac{2}{3}x - 13 = 7 }[/tex]

Adding 13 to both sides we get :

[tex]\qquad \sf \: { \dashrightarrow \dfrac{2}{3}x - 13 + 13 = 7 + 13 }[/tex]

[tex]\qquad \sf \: { \dashrightarrow \dfrac{2}{3}x = 20 }[/tex]

Now, Multiplying both sides by [tex] \dfrac{3}{2} [/tex] we get :

[tex]\qquad \sf \: { \dashrightarrow \dfrac{2}{3}x \times \dfrac{3}{2} = 20 \times \dfrac{3}{2} }[/tex]

[tex]\qquad \sf \: { \dashrightarrow \dfrac{ \cancel2}{ \cancel3}x \times \dfrac{{ \cancel3}}{ \cancel{2}} = \cancel{20} \times \dfrac{3}{ \cancel{2}} }[/tex]

[tex]\qquad \sf \: { \dashrightarrow x = 10 \times {3} }[/tex]

[tex]\qquad \bf \: { \dashrightarrow x = 30 }[/tex]

Therefore, The number is 30.