Respuesta :
Answer:
30
Step-by-step explanation:
Let,
The req. number be = x
So,
Two - thirds of the number
[tex] = \frac{2}{3} x[/tex]
Then, it is reduced by 13
[tex] = \frac{2}{3} x - 13[/tex]
After that,
The req. result we get is = 7
Therefore,
By the problem,
[tex] = > \frac{2}{3} x - 13 = 7[/tex]
- (On putting like terms on one side)
[tex] = > \frac{2}{3} x = 7 + 13[/tex]
- (On Simplification)
[tex] = > \frac{2}{3}x = 20[/tex]
- (On multiplying both sides with 3/2)
[tex] = > \frac{2}{3} x \times \frac{3}{2} = 20 \times \frac{3}{2} [/tex]
- (On Simplification)
=> x = 30
Hence,
The req. number is 30.
Given that :
- Thirteen is reduced by two-thirds of a number. And their result is 7.
To Find :
- The number.
Solution :
Let's assume the number as x
According to the question :
[tex]\qquad \sf \: { \dashrightarrow \dfrac{2}{3}x - 13 = 7 }[/tex]
Adding 13 to both sides we get :
[tex]\qquad \sf \: { \dashrightarrow \dfrac{2}{3}x - 13 + 13 = 7 + 13 }[/tex]
[tex]\qquad \sf \: { \dashrightarrow \dfrac{2}{3}x = 20 }[/tex]
Now, Multiplying both sides by [tex] \dfrac{3}{2} [/tex] we get :
[tex]\qquad \sf \: { \dashrightarrow \dfrac{2}{3}x \times \dfrac{3}{2} = 20 \times \dfrac{3}{2} }[/tex]
[tex]\qquad \sf \: { \dashrightarrow \dfrac{ \cancel2}{ \cancel3}x \times \dfrac{{ \cancel3}}{ \cancel{2}} = \cancel{20} \times \dfrac{3}{ \cancel{2}} }[/tex]
[tex]\qquad \sf \: { \dashrightarrow x = 10 \times {3} }[/tex]
[tex]\qquad \bf \: { \dashrightarrow x = 30 }[/tex]
Therefore, The number is 30.