Suppose you have a right triangle called △MNP where ∠N is the right angle. If MN = 6 and MP = 17, which can be used to find m∠P?

arcsin(6/17) can be used to find m∠P in the right angled triangle.
Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.
let m∠P be represented as θ, hence using trigonometric ratio:
sinθ = MN/MP
substituting values:
sinθ = 6/17
θ = sin⁻¹(6/17)
m∠P = sin⁻¹(6/17)
arcsin(6/17) can be used to find m∠P in the right angled triangle.
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