Respuesta :

Answer:   Germanium has a cubic closest packed structure as a solid. Assuming that germanium has an atomic radius of 159 pm, calculate the density of solid germanium. __________ g/cm3 b.) Germanium has a face-centered cubic unit cell. The density of germanium is 5.32 g/cm3. Calculate a value for the atomic radius of germanium. ___________pm c.) You are given a small bar of an unknown metal X. You find the density of the metal to be 12.0 g/cm3. An X-ray diffraction experiment measures the edge of the face-centered cubic unit cell as 3.89 â„« (1 â„« = 1 ✕ 10−10 m). Identify X.

Explanation:

The density of Germanium is equal to 5.30g/cm^3

Data Given;

  • atomic radius = 159pm

For a cubic closest packed = 4r

[tex]4r = \sqrt{2a} \\ a = \frac{4}{\sqrt{2} }r\\ a = \frac{4}{2}*159*10^-^1^0\\ a = 4.50*10^-^8cm[/tex]

Density of the cube

The density of the cube is given as the ratio between the mass and volume. But in this case, we have a formula

[tex]d = \frac{Zm}{Na^3}\\ d = \frac{4*72.64}{6.023*10^2^3*9.09*10^-^2^3}\\ d = 5.30 g/cm^3[/tex]

NB;

  • Z = number of face
  • m = molar mass
  • N = Avogadro's constant
  • a = side length

The density of the cube is equal to 5.30g/cm^3

Learn more about structure of an atom;

https://brainly.com/question/8437294

Otras preguntas