Considering the definition of STP conditions, 28 grams of O₂ will ocupy at STP 19.6 L.
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
On the other side, the molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
In this case, you have 28 g of O₂. The molar mass es 32 [tex]\frac{g}{mole}[/tex]
Next, you can apply the following rule of three: if 32 grams of the compound are contained in 1 mole, 28 grams are contained in how many moles?
[tex]number of moles=\frac{28 gramsx1 mole}{32 grams}[/tex]
number of moles= 0.875 moles
Now, you can apply the following rule of three: if by definition of STP conditions 1 mole of O₂ occupies a volume of 22.4 liters, 0.875 moles occupies how much volume?
[tex]volume=\frac{0.875 molesx22.4 L}{1 mole}[/tex]
volume= 19.6 L
Finally, 28 grams of O₂ will ocupy at STP 19.6 L.
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