Respuesta :

Answer:

c. Force applied is 75 N

EDITED

tan 37 = a/g

a = 3g/4

a in equation

t× 3/5 = 2 × 3g/4

t = 5× 10/2

t = 25n

f = ma

f = ( mt + mb )a

F = 10 × 3× 10/4

F = 75 n

• Correct option is (C).

We know that the angle made by string is θ=

[tex]tan {}^{ - 1} ( \frac{a}{g} )[/tex]

where a is the acceleration of the frame in which the string is hanging in our case it is a trolley.

[tex]putting  \: θ=37° \: or \: tan \: 37° = \frac{3}{4} [/tex]

[tex]we \: get \: a \: \frac{3g}{4} = \frac{30}{4} = 7.5 \: m/s^2[/tex]

[tex] \boxed{Force \:  F=total  \: mass \:  of \:  the  \: system \:  on  \: which  \: force  \: is  \: acting ×acceleration  \: of  \: the  \: system=(8+2)×7.5=75 }[/tex]

[tex] \boxed{ so \: force \: is \: 75 \:N. }[/tex]