Respuesta :

[tex]\\ \sf\longmapsto {\displaystyle{\lim_{x\to 1}}}\dfrac{x^2-1}{x-1}[/tex]

[tex]\\ \sf\longmapsto {\displaystyle{\lim_{x\to 1}}}\dfrac{x^2-1^2}{x-1}[/tex]

[tex]\\ \sf\longmapsto 2(1)^(2-1)[/tex]

[tex]\\ \sf\longmapsto 2(1)[/tex]

[tex]\\ \sf\longmapsto 1[/tex]

HayabusaBrainly

Step-by-step explanation:

[tex] \tt \lim \limits_{x \to1} \frac{ {x}^{2} - 1 }{x - 1} = ...[/tex]

[tex] = \tt \lim \limits_{x \to1} \frac{(x + 1) \cancel{(x - 1)}}{ \cancel{(x - 1)}} [/tex]

[tex] = \tt \lim \limits_{x \to1}(x + 1)[/tex]

[tex] = \tt1 + 1[/tex]

[tex] = \boxed{ \bold{ \blue{ \underline2}}}[/tex]

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