contestada

1. m_ADC=3x+10 and m~BC=2X-30,what is m™AC
2. m2BDC=3(x-5) and m--BC=x+25,what is MZA
3. m2A= 1/2 (x-10)and m_C=1/3 x+5,find m-BC
4. if m(BC)=4x-6 and m_C=x+10,waht is m_BDC?

1 mADC3x10 and mBC2X30what is mAC 2 m2BDC3x5 and mBCx25what is MZA 3 m2A 12 x10and mC13 x5find mBC 4 if mBC4x6 and mCx10waht is mBDC class=