Explanation:
(I). 5/6 (4X+8) = (3/8) X - (1/4)
→ [{5(4X) + 5(8)}/6] = (3/8)X - (1/4)
→ [{20X + 40}/6] = (3/8)X - (1/4)
→ [{(20X/6) + (40/6) = (3/7)X - (1/4)
Now,
shift all variables fraction on LHS and constant fraction on RHS.
→ [(20X/6) - (3X/7)]= -(1/4) - (40/6)
Take the LCM of LHS denominator of 6&7 is 42.
→ [(140X - 18X)/42] = -(1/4)-(40/6)
→ [(122X)/42] = -(1/4)-(40/6)
Again take the LCM of the denominator in RHS i.e 4&6 is 12.
→ [(122X)/42] = (-12 - 80)/4
→ [(122X)/42] = (-92)/4
By doing Cross multiply the fraction, we get
→ 4(122X) = 42(-92)
→ 488X = -3 864
→ X = -3 864÷488
Therefore, X = -3864/488
Answer: Hence, the value of X for the given problem is -3864:488.
Explanation:
ii)Given algebraic equation is: 5(3p-5)+4p=5p-6(p+4)
→ 15p - 25 + 4p = 5p - 6p + 24
Shift all variables in LHS and constant on RHS.
→ 15p + 4p +6p = 25+24
→ 19p + 6p = 49
→ 25p = 49
Shift the number 25 from LHS to RHS.
Therefore, p = 49/25.
Answer: Hence, the value of P for the given algebraic equation is 49/25.
