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Easy question
A father is 35 years more than his son’s age. After 5 years the father’s age will be twice of his son’s age.Find the present age of both.​

Respuesta :

raphealnwobi

The son is 30 years and the father is 65 years.

Let x represent the present age of the son and y represent the present age of the father.

Hence:

y = x + 35

-x + y = 35    (1)

In 5 years time:

y + 5 = 2(x + 5)

y + 5 = 2x + 10

-2x + y = 5  (2)

Solving equations 1 and 2 simultaneously gives:

x = 30, y = 65

The son is 30 years and the father is 65 years.

Find out more on equation at: https://brainly.com/question/2972832

fieryanswererft

Son   =  30 years

Father  =  65 years

Present Details:

Son: "s" years                    (lets consider son's present age to be s)

Father: "s + 35"                  (father is 35 years older than the son)

After 5 years:

Son: "s + 5"                [son will be 5 years older]

Father: 2(s + 5)     [twice the son's age]  and  (s + 35) + 5 = (s + 40) years

Solve father's age simultaneously:

  • 2(s + 5) = (s + 40)
  • 2s + 10 = s + 40
  • 2s - s = 40 - 10
  • s = 30

⊕ Thus, the Son is 30 years old.

Father's age:

  • s + 35 ⇒ 30 + 35 ⇒ 65 years

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