The molar mass of ammonium acetate is 77.083 g/mol. A student uses 0.100 mol of ammonium acetate in a chemical reaction. The student claims that the reaction uses ( 0.100 mol ) ( 77.083 g/mol ) = 7.71 g of ammonium acetate, which has ( 7.71) (6.022 X 10^23) = 4.64 X 10^24 molecules.

In one to two sentences, explain the mistake that the student made and determine the correct number of molecules of ammonium acetate used in the reaction.

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Answer:

The mistake here is the fact the student turned the moles back into mass and then multiplied the mass by Avogadro's number (6.02 x [tex]10^{23}[/tex]), which gave him a false answer. To get the correct answer, he had to multiply the number of moles of ammonium acetate by Avogadro's number for the number of molecules.

[tex]Number\ of\ molecules\ =\ moles\ * \ Avogadro's\ number[/tex]

[tex]Number \ of \ molecules\ =\ 0.100 \ * \ (6.02 * 10^2^3)[/tex]

[tex]Number \ of \ molecules = 6.02\ * \ 10^{22}[/tex]

The correct number of molecules of ammonium acetate used in the reaction is 6.02 x [tex]10^{22}[/tex] moles

The correct number of molecules of ammonium acetate used in the reaction is 0.60 × 10²³.

What is Avogadro's number?

Avogadro's numbers are those numbers which tells about the number of atoms present in one mole of any substance and it is equal to the 6.022 × 10²³.

In the question given that 0.100 mole of ammonium acetate is present and for finding the molecules of ammonium acetate we have to multiply the given moles with the avogadro's numbers as:

No. of molecules = 0.100 × 6.022 × 10²³ = 0.60 × 10²³.

But student convert rhe moles into mass and then multiply with the avogadro's numbers which leads to the wrong answer.

Hence, correct number of molecules of ammonium acetate is 0.60 × 10²³.

To know more about avogadro's numbers, visit the below link:
https://brainly.com/question/1581342