- Sample space of a throwing of a die - {1, 2, 3, 4, 5, 6}
- Number of trial = 6
- Numbers which are even = 2, 4, 6
- Number of number which are even = 3
- Therefore, probability of getting an even number
- [tex] = \frac{3}{6} = \frac{1}{2} [/tex]
Answer:
[tex]b) \frac{1}{2} [/tex]
Hope you could get an idea from here.
Doubt clarification - use comment section.
