Respuesta :
The dvd player’s price was reduced by $3. 82 more than the stereo tuner’s price.
- Let the cost price of dvd players be D.
- Let the cost price of stereo tuners be S.
Given the following data:
- Markdown for dvd player = 36%
- Markdown for stereo tuner = 22%
- Markdown cost for dvd player = $41.60
- Markdown cost for stereo tuner = $69.42
To determine which item’s price was reduced by more, and by how many dollars:
First of all, we would calculate the cost price of each item.
For dvd players:
Note: You'll pay 64% since it was markdown by 36%.
[tex]\frac{64}{100} \times D = 41.60\\\\64D=41.60 \times 100\\\\64D=4160\\\\D=\frac{4160}{64}[/tex]
D = $65
Reduction: Dvd player = [tex]65-41. 60=[/tex] $23.40
For stereo tuners:
Note: You'll pay 78% since it was markdown by 22%.
[tex]\frac{78}{100} \times S = 69.42\\\\78S=69.42 \times 100\\\\78S=6942\\\\S=\frac{6942}{78}[/tex]
D = $89
Reduction: Stereo tuner = [tex]89-69. 42=[/tex] $19.58
Now, we can calculate the difference in reduction of the cost price of both items:
[tex]Difference = 23.4 -19.58[/tex]
Difference = $3.82
Therefore, the price of the dvd players was reduced by $3. 82 more than the price of the stereo tuners.
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