A flexible vessel contains 78.00 L of gas at a pressure of 1.50 atm. Under conditions of constant temperature
and moles of gas, what is the pressure of the gas when the volume of the vessel is tripled?

Respuesta :

The pressure of the gas when the volume of the vessel is tripled is 0.50 atm.

To find the volume of the gas, we use Boyle's law which states that for a given mass of gas at constant temperature, the pressure is inveresly proportional to its volume. This is stated mathematically as P ∝ 1/V.

So, PV = constant

P₁V₁ = P₂V₂ where P₁ = initial pressure of gas = 1.50 atm, P₂ = final pressure of gas, V₁ = initial volume of gas = 78.00 L and V₂ = final volume of gas = 3V₁ (since the volume of the gas is tripled)

So, making P₂ the subject of the formula, we have

P₂ = P₁V₁/V₂

Substituting the values of the variables into the equation, we have

P₂ = P₁V₁/V₂

P₂ = 1.50 atm × V₁/3V₁

P₂ = 1.50 atm/3

P₂ = 0.50 atm

So, the pressure of the gas when the volume of the vessel is tripled is 0.50 atm.

Learn more about Boyle's law here:

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