The probability that an athlete that is getting into a fight has a tattoo is 0.80
Let the events be represented as:
So, the probabilities are given as:
[tex]P(A\ n\ B) = 40\%[/tex]
[tex]P(A) = 50\%[/tex]
The probability that an athlete that is getting into a fight has a tattoo is represented as: P(B | A)
So, we have:
[tex]P(B | A) = \frac{P(A\ n\ B)}{P(A)}[/tex]
Substitute known values
[tex]P(B | A) = \frac{40\%}{50\%}[/tex]
Cancel out the percentages
[tex]P(B | A) = \frac{40}{50}[/tex]
Divide 40 by 50
[tex]P(B | A) = 0.80[/tex]
Hence, the probability that an athlete that is getting into a fight has a tattoo is 0.80
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