The remainder of the equation is [tex]\rm x+1[/tex].
Given that,
When the equation is [tex]x^3+1[/tex] divided by [tex]x^2-x+1[/tex].
We have to determine,
The remainder for the equation?
According to the question,
The equation [tex]x^3+1[/tex] is divided by [tex]x^2-x+1[/tex].
On the division of the polynomial, the remainder is,
[tex]\dfrac{\rm x^3+1}{x^2-x+1}[/tex]
Factorize the equation to convert this into the simplest form,
[tex]\rm = x^3+1\\\\=x^3-x^2+x + x^2-x+1\\\\= x ( x^2-x+1) + 1(x^2-x+1)\\\\= (x+1) (x^2-x+1)[/tex]
Now, the equation can be written as,
[tex]\rm = \dfrac{(x+1) (x^2-x+1) }{ x^2-x+1}\\\\= x+1[/tex]
Hence, The required remainder of the equation is [tex]\rm x+1[/tex].
For more details refer to the link given below.
https://brainly.com/question/25880057
