The given equation [tex](6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)[/tex] is equivalent to the expression -3c.
Given that, the expression can be written as.
[tex](6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)[/tex]
By simplifying the above equation,
[tex]\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}[/tex]
By taking out the common terms from the equation,
[tex]\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}[/tex]
By simplifying the above equation by cancel out the common factors.
[tex]\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}[/tex]
Now, by taking (-1) common from (-2c+1) we get,
[tex]\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}[/tex]
By simplifying the above equation, we get the expression,
[tex]-3c[/tex]
So the given equation [tex](6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)[/tex] is equivalent to the expression -3c.
For more details, follow the link given below.
https://brainly.com/question/1301963.
