Respuesta :
Answer:
n-1,n,n+1
Step-by-step explanation:
let the numbers be x,x+1,x+2
x+x+1+x+2=3n
3x+3=3n
3x=3n-3
x=1/3 (3n-3)=n-1
so mumbers are n-1,n,n+1
The three consecutive numbers are n-1, n, and n+1.
We have to determine, the three consecutive numbers if their sum is 3n.
According to the question,
The consecutive number series can be even as well as odd depending on the first term of the series and the difference between the numbers.
Let, the three consecutive numbers be x, x+1, and x+2.
The sum of three consecutive numbers is equal to 33.
[tex]\rm x + x+1+x+2=3n\\\\3x+3 = 3n \\\\Divided \ by \ 3 \ on \ both \ the \ sides \\\\x +1 = n\\\\x = n-1[/tex]
Therefore,
The first consecutive number is,
[tex]\rm x = n-1[/tex]
The second consecutive number is,
[tex]\rm x+1 = n-1+1 = n\\[/tex]
The third consecutive number is,
[tex]\rm x+2= n-1+2 = n+1\\[/tex]
Hence, The three consecutive numbers are n-1, n, and n+1.
For more details refer to the link given below.
https://brainly.com/question/16048559
