The population of certain city is projected to grow at the rate of r(t) = 400 1+ people/ 24 +7 year in interval (Osts 5) t years from now. The current population is 60 000. What will be the population 5 years from now?​

Respuesta :

The population 5 years from now would be 60482

The population growth rate is given as:

[tex]r(t) = 400(1 + \frac{2t}{24 + t^2})[/tex]

The value of t, 5 years from now is represented as:

t = 5

Substitute 5 for t in the function r(t).

So, we have:

[tex]r(5) = 400(1 + \frac{2 \times 5}{24 + 5^2})[/tex]

Evaluate the exponent

[tex]r(5) = 400(1 + \frac{2 \times 5}{24 + 25})[/tex]

Evaluate the products

[tex]r(5) = 400(1 + \frac{10}{24 + 25})[/tex]

So, we have:

[tex]r(5) = 400(1 + \frac{10}{49})[/tex]

Divide 10 by 49

[tex]r(5) = 400(1 + 0.204)[/tex]

This gives

[tex]r(5) = 400(1.204)[/tex]

Expand

[tex]r(5) = 481.6[/tex]

The current population is given as 60000.

So, the population (P) 5 years from now would be

[tex]P = 60000 + 481.6[/tex]

[tex]P = 60481.6[/tex]

Approximate

[tex]P = 60482[/tex]

Hence, the population (P) 5 years from now would be 60482

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