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3.) Jason has one less dimes than quarters and twice as many nickels

as quarters. If he has a total of $4.40, how many of each type

coin does he have?

Respuesta :

Answer:

10 quarters, 9 dimes, and 20 nickels.

Step-by-step explanation:

q - 1 = d, 2q = n or q = 1/2n

.25q + .10(q - 1) + .05(2q) = 4.40

.25q + .10q - .10 + .10q = 4.40

.45q - .10 = 4.40

.45q = 4.50

4.5/.45 = 10

He has 10 quarters, 9 dimes, and 20 nickels.

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