The probability that detector B goes off is 0.75
The probability of an event is known to be the likelihood or chance for an event to occur.
From the given information let consider:
Since one or both of them always goes off, then:
∴
Their complements will be zero, i.e.
Similarly, we are given that:
Then;
∴
The set probability for A will be:
P(A) = 1 - P(A')
P(A) = 1 - 0.35
P(A) = 0.65
Finally, the probability that detector B goes off can be computed as:
P(B) = P(A) P(B|A) +P(A') P(B|A')
P(B) = P(A) (1 - P(B|A')) + P(A') (1 - P(B'|A')
[tex]\mathbf{P(B) = P(A) (1-\dfrac{P(A \ and \ B')}{P(A)}) +P(A') (1 - \dfrac{P(A' \ and B')}{P(A')})}[/tex]
[tex]\mathbf{P(B) = 0.65 (1-\dfrac{0.25}{0.65}) +0.35 (1 - \dfrac{0}{0.35})}[/tex]
P(B) = 0.75
Learn more about the probability of an event here:
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