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Knowing that the solubility of a salt at 80°C is 45g/100 g of H,O, calculate the mass of water required for dissolve 250 g of this salt at 80º C.​

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The mass of water required will be approximately [tex] \bf = 555.6\: g [/tex].

  • To solve this question, just make a simple rule of three between the amount of salt dissolved at 80ºC and the mass of water:

[tex]\qquad[/tex] 45g of salt [tex] \sf \longrightarrow[/tex] 100g of H₂O

[tex]\qquad[/tex] 250g of salt [tex] \sf \longrightarrow[/tex] x g of H₂O

[tex]\qquad[/tex] [tex]\red{\twoheadrightarrow\bf45\times x = 250\times 100}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf45x=25000[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf x=\cancel{\dfrac{25000}{45}}[/tex]

[tex]\qquad[/tex] [tex]\red{\twoheadrightarrow\bf x = 555.6\:g}[/tex]

  • Therefore, knowing that the solubility of a salt at 80ºC is 45g/100g of water (H₂O), the mass of water needed to dissolve 250g of this salt at 80ºC will be [tex] \red{\bf = 555.6\: g }[/tex]

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