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What is the equation of a line with a slope of 4 that passes
through point (-2,5)? A y = -1/4x - 3 B y = -4x + 5 C y = 4x + 5 D y = 4x + 13

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msm555

Answer:

Solution given:

slope(m)=4

passes through (x',y')=(-2,5)

we have

equation of a line is:

y-y'=m(x-x')

substituting value we get

y-5=4(x-(-2))

y-5=4(x+2)

y-5=4x+8

y=4x+8+5

y=4x+13 is a required equation of a line.

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