The correct option is B. (1,4).
Given equations,
[tex]2x=-y+6....(1)\\-4x+3y=8....(2)[/tex]
We have to find the solution of the given system of equations.
Equation 2 can be written as,
[tex]-2\times(2x)+3y=8\\[/tex]
Now by substitution method, putting the value of [tex]2x[/tex] from Equation (1) in above equation, we get
[tex]-2\times(-y+6)+3y=8\\2y-12+3y=8\\5y-12=8\\5y=20\\y=4[/tex]
Now putting the value of y in equation 1 we get,
[tex]2x=-4+6\\2x=2\\x=1[/tex]
Hence the solution of the given system of equation will be (1,4).
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