A system of equations is shown: 2x = â’y 6 â’4x 3y = 8 What is the solution to this system of equations? (â’1, â’4) (1, 4) (4, 1) (â’4, â’1).

Respuesta :

The correct option is B. (1,4).

Given equations,

[tex]2x=-y+6....(1)\\-4x+3y=8....(2)[/tex]

We have to find the solution of the given system of equations.

Equation 2 can be written as,

[tex]-2\times(2x)+3y=8\\[/tex]

Now by substitution method, putting the value of [tex]2x[/tex] from Equation (1) in above equation, we get

[tex]-2\times(-y+6)+3y=8\\2y-12+3y=8\\5y-12=8\\5y=20\\y=4[/tex]

Now putting the value of y in equation 1 we get,

[tex]2x=-4+6\\2x=2\\x=1[/tex]

Hence the solution of the given system of equation will be (1,4).

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