The value of x is 3.
Given that,
If [tex]5 + 20 \times 2^{2-3x}[/tex],
And Baseline = [tex]10 \times 2^{-2x}+5[/tex]
We have to find,
The value of x?
According to the question,
To determine the value of x in the equation following all the steps given below.
Equation; [tex]\rm 5 + 20 \times 2^{2-3x} = 10 \times 2^{-2x}+5[/tex]
[tex]\rm5- 5 + 20 \times 2^{2-3x} = 10 \times 2^{-2x}+5-5\\\\\rm 20 \times 2^{2-3x} = 10 \times 2^{-2x}[/tex]
[tex]\rm 20 \times 2^{2-3x} = 10 \times 2^{-2x}\\\\\dfrac{ 20 \times 2^{2-3x} }{10}= \dfrac{10 \times 2^{-2x}}{10}\\\\\rm 2 \times 2^{2-3x} = 2^{-2x}[/tex]
[tex]\rm 2 \times 2^{2-3x} = 2^{-2x}\\\\2^1 \times 2^{2-3x} = 2^{-2x}\\\\2^{2-3x+1} = 2^{-2x}\\\\[/tex]
[tex]\rm 2-3x+1 = -2x\\\\-3x+2x = -1-2\\\\-x = -3\\\\x=3[/tex]
Hence, The required value of x is 3.
For more details about the Exponent refer to the link given below.
https://brainly.com/question/25959524