Answer:
7x+8y=32
Step-by-step explanation:
Hi there!
We are given the following equation:
[tex]y=-\frac{7x}{8} +4[/tex]
And we want to convert it into standard form
Standard form is ax+by=c, where a, b, and c are integer coefficients, a and b cannot be zero, and a cannot be negative
a is the coefficient in front of x and b is the coefficient in front of y
Since we have the term with x ([tex]-\frac{7x}{8}[/tex]) on the right side, and we want it on the left side with the term with y, we can move it to the other side, by adding [tex]\frac{7x}{8}[/tex] to both sides.
[tex]y=-\frac{7x}{8} +4[/tex]
+[tex]\frac{7x}{8}[/tex] +[tex]\frac{7x}{8}[/tex]
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[tex]\frac{7x}{8} + y =4[/tex]
Now we have the terms of x and y on both sides, but remember; we want the coefficients to be integers (whole numbers).
We'll need to clear the fraction of [tex]\frac{7x}{8}[/tex]. To do that, we can multiply both sides by 8.
[tex]8(\frac{7x}{8} + y) =8(4)[/tex]
Now doing the distributive property:
[tex]8(\frac{7x}{8}) + 8(y) =8(4)[/tex]
Multiply each term by 8.
7x + 8y = 32
Hope this helps!
