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. A teacher pushes a desk across the floor for a distance of 5 meters. She exerted a horizontal force of 20N. How much work was done?

Respuesta :

  • Force (F) = 20 N
  • Distance (s) = 5 m
  • Angle between the force and distance (Θ) = 0°
  • We know, work done = Fs Cos Θ
  • Therefore, the work done by the teacher
  • = (20 × 5 × Cos 0°) J
  • = (20 × 5 × 1) J
  • = 100 J

Answer:

100 J work was done.

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