Respuesta :
Answer:
a-2=a-2
Step-by-step explanation:
Here it is, you just have to notice that the numerator has common factors alternated. You will then collect the same parentheses and simplify with the denominator.

Answer:
Step-by-step explanation:
Parentheses are missing in your problem statement if you intend to simplify ...
[tex]\dfrac{3a^2-ac+2c-6a}{3a-c}\\\\=\dfrac{a(3a-c) -2(3a-c)}{3a-c}\qquad\text{factor pairs of terms}\\\\=\dfrac{(a-2)(3a-c)}{(3a-c)}\\\\=\boxed{a-2}\qquad\text{cancel common factors}[/tex]
The "steps" are ...
- factor numerator (and denominator, if necessary)
- cancel common factors