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3a² - ac + 2c - 6a/ 3a - c = a - 2

i have been looking everywhere but i cannot find the steps on how to simplify/solve this
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Respuesta :

Answer:

a-2=a-2

Step-by-step explanation:

Here it is, you just have to notice that the numerator has common factors alternated. You will then collect the same parentheses and simplify with the denominator.

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Answer:

Step-by-step explanation:

Parentheses are missing in your problem statement if you intend to simplify ...

  [tex]\dfrac{3a^2-ac+2c-6a}{3a-c}\\\\=\dfrac{a(3a-c) -2(3a-c)}{3a-c}\qquad\text{factor pairs of terms}\\\\=\dfrac{(a-2)(3a-c)}{(3a-c)}\\\\=\boxed{a-2}\qquad\text{cancel common factors}[/tex]

The "steps" are ...

  • factor numerator (and denominator, if necessary)
  • cancel common factors