Answer: 65£40625
Step-by-step explanation:
We know that there are already 150L of oil in the tank. So if we want to fill the tank, we need to add 1250L to fill the rest of the tank. The price of 1L of oil is 80.5p, which can be represented as [tex]\frac{80.5p}{L}[/tex]. If we want to know the price of the remaining 1250L, then we can multiply the denominator by 1250 because that way we can find the cost in p of 1250L. Now if you want to keep the ratio of the original equation to the cost of 1250L equal (or just keeping both expressions equal), then we also have to multiply the numerator by 1250. So, we then get [tex]\frac{(1250)(80.5p)}{(1250)(L)}[/tex]=[tex]\frac{100625p}{1250L}[/tex]. So the cost of 1250L is 100625p.
Now, applying the discount. To apply a discount x to some value y:
x - xy, where x = original value, y = discount.
So, substituting the original value of 100625p for x and the discount 6.5% = 0.065 for y, we get: (100625) - [(100625)(0.065)]. The question, however, doesn't ask for the discounted price, but rather the discount itself, or how much money you save. The expression xy gives us just that.
So, (100625)(0.065) gets us to to 6540.625p = 65£40625.
