Respuesta :
Answer:
Step-by-step explanation:
Let A be cost of adult ticket
Let C be cost of child ticket
5A + 4C = 22
A = (22 - 4C)/5
Β Β Β Β Β Β Β Β 24A + 2C = 54
24((22 - 4C)/5) + 2C = 54
Β 105.6 - 19.2C + 2C = 54
Β Β Β Β Β Β Β Β Β Β Β - 17.2C = - 51.6
Β Β Β Β Β Β Β Β Β Β Β Β Β Β C = $3.00
A = (22 - 4(3))/5 = $2.00
Step-by-step explanation:
Let,
Senior tickets = x
Child tickets = y
In case 1
5x + 4y = 22 (1)
In case 2
24x + 2y = 54
On multiplying both sides by 2
48x + 4y = 108 (2)
On subtracting 1 and 2
48x + 4y - (5x + 4y) = 108 - 22
48x + 4y - 5x - 4y = 86
43x = 86
x = 86/43
x = 2
From 1
5(2) + 4y = 22
10 + 4y = 22
4y = 22 - 10
4y = 12
y = 12/4
y = 3
Hence,
Cost of 1 child ticket = $ 2
Cost of 1 adult ticket = $ 3