The height of the tower is 150 m
To get the height of the tower, we will use the SOH CAH TOA identity as shown:
tan theta = opp/adj
tan 30 = x/CD
CD = x/tan30
Similarly;
tan 60 = x+100/CD
CD = x+100/tan60
Equating both sides CD
x/tan30 = x+100/tan60
x/x+100 = tan30/tan60
x/x+100 = 0.5773/1.732
x/x+100 = 0.3333
x = 0.333x + 33.33
x - 0.333x = 33.33
0.6667x = 33.33
x = 50 m
Height of the tower = x + 100 = 150m
Hence the height of the tower is 150 m
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