Answer:
Step-by-step explanation
In the form ax^2+bx+c
a x c should equal two factors of b
However, in this equation
1 x 19 has no factors that = 10
so you must use the Quadratic Formula which is,
x = [tex]\frac{-b+-\sqrt{b^2-4ac} }{2a} [/tex]
so the answer should be
x = [tex]\frac{-10+-\sqrt{10^2-4(1)(19)} }{2(1)} [/tex]
x = [tex]\frac{-10+-\sqrt{24} }{2} [/tex]
x = [tex]\frac{-10+2\sqrt{6} }{2} [/tex] and x = [tex]\frac{-10-2\sqrt{6} }{2} [/tex]
