Respuesta :
Explanation:
T1 = 201k
T2 = 537k
C1 = 1220 m / s
C1/C2 =√(T1/T2)
C2 = C1×√(T2/T2)
C2 = 1220×√(537/201)
C2 = 1220 × √(179/67)
C2 = (1220√179)/(√69)
C2 = (1220√11993)/67 ≈ 1994.10924
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The speed of sound when the temperature rises is 1988.6 m/s.
Speed of sound when the temperature rises
The speed of sound when the temperature rises is calculated as follows;
[tex]C_2 = C_1 \times \sqrt{\frac{T_2}{T_1} }[/tex]
where;
- C1 is the initial speed = 1220 m/s
- T1 is the initial temperature = 201 K
- T2 is the final temperature = 537 K
- C2 is the final speed = ?
The final speed of sound is calculated as follows;
[tex]C_2 = 1220 \times \sqrt{\frac{537}{201} } \\\\C_2 = 1988.6 \ m/s[/tex]
Learn more about speed of sound with temperature here: https://brainly.com/question/14400858