Respuesta :
[tex](\stackrel{x_1}{-3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{7}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{7}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{0+3}\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{1}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-4=x+3\implies y=x+7[/tex]
Answer:
y = x + 7
Step-by-step explanation:
Slope m = (y2-y1)/(x2-x1)
given (-3,4) and (0,7)
m = (7 - 4)/(0 - -3) = 3/3 = 1
Slope-intercept: y = mx + b
using (0,7)
7 = 1(0) + b
b = 7
then y = 1x + 7
y = x + 7
