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A coal barge with a mass of 2.36 × 10^4 kg drifts along a river. When it passes under a coal hopper, it is loaded with 9.4 × 10^3 kg of coal. What is the speed of the unloaded barge if the barge after loading has a speed of 2.7 m/s?

Respuesta :

nuralfaqih

Known :

m = 2.36 × 10⁴ kg

M = 9.4 × 10³ kg

V = 2.7 m/s

Solution :

Using the principle of momentum

m • v = (m + M) • V

(2.36 × 10⁴) • v = (2.36 × 10⁴ + 9.4 × 10³)(2.7)

v = 3.77 m/s

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