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mazzazfarrah4 mazzazfarrah4

24-01-2022
Mathematics

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SalmonWorldTopper SalmonWorldTopper · Answer 1 · 2022-01-24T11:54:17+01:00

Answer:

(1/8){7x+(1/5)}

Step-by-step explanation:

Given that:

(3/4){(5/6)x} - (3/5){-(1/6)} - 2x(-3/8) = ?

= (3/4) * (5/6)x - (3/5){-(1/6)} - 2x(-3/8)

= (5x/8) + (3/5) * (1/6) - 2x(-3/8)

= (5x/8) + 1/(5*2) - 2x(-3/8)

= (5x/8) + (1/10) - 2x(-3/8)

= (5x/8) + (1/10) - x(-3/4)

= (5x/8) + (1/10) +(3x/4)

= (5x/8) + (3x/4) + (1/10)

Take the LCM of the denominator 4 and 8 is 8.

= {(7x*1 + 3x*2)/8} + (1/10)

= {(7x + 6x)/8} + (1/10)

= {(7x)/8} + (1/10)

= (7x/8) + (1/10)

Take the LCM of the denominator 8 and 10 is 40.

= {(7x*5 + 1*1)/40}

= {(35x + 1)/10}

= (7x/8) + (1/40)

= (1/8){7x+(1/5)} Ans.

Please let me know if you have any other questions.

Аноним Аноним · Answer 2 · 2022-01-24T12:01:13+01:00

Answer:

[tex] \rm \longmapsto \: \frac{3}{4} ( \frac{5x}{6} ) + \frac{ - 3}{5} ( \frac{ - 1}{6} ) - 2x( \frac{ - 3}{8} )[/tex]

[tex]\sf \longmapsto \: \frac{3}{4} \times \frac{5x}{6} + \frac{ - 3}{5} ( \frac{ - 1}{6} ) - 2x( \frac{ - 3}{8} )[/tex]

[tex]\sf \longmapsto \: \frac{3 \times 5x}{4 \times 6} + \frac{ - 3}{5} ( \frac{ - 1}{6} ) - 2x( \frac{ - 3}{8} )[/tex]

[tex]\sf \longmapsto \: \frac{15x}{24} + \frac{ - 3}{5} ( \frac{ - 1}{6} ) - 2x( \frac{ - 3}{8} )[/tex]

[tex]\sf \longmapsto \: \frac{5x}{8} + \frac{ - 3}{5} ( \frac{ - 1}{6} ) - 2x( \frac{ - 3}{8} )[/tex]

[tex]\sf \longmapsto \: \frac{5x}{8} + \frac{1}{10} - 2x( \frac{ - 3}{8} )[/tex]

[tex]\sf \longmapsto \: \frac{5x}{8} + \frac{1}{10} + \frac{3}{4} x[/tex]

[tex]\sf \longmapsto \: \frac{5x}{8} + \frac{1}{10} + \frac{3x}{8} [/tex]

[tex]\sf \longmapsto \: \frac{5x + \frac{4}{5} + 2 \times 3x}{8} [/tex]

[tex]\sf \longmapsto \: \frac{5x + \frac{4}{5} + 6x}{8} [/tex]

Combine like terms:

[tex]\sf \longmapsto \: \frac{5x + 6x + \frac{4}{5} }{8} [/tex]

[tex]\sf \longmapsto \: \frac{11x + \frac{4}{5} }{8} [/tex]

Please help me out with this problem ​

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Please help me out with this problem