- Mass=m=44.9kg
- Distance=s=20.5m
- initial velocity=u=0m/s
- Final velocity=v=62m/s
- Force=F
- Acceleration=a
Using third equation of kinematics
[tex]\\ \tt\longmapsto v^2-u^2=2as[/tex]
[tex]\\ \tt\longmapsto a=\dfrac{v^2-u^2}{2s}[/tex]
[tex]\\ \tt\longmapsto a=\dfrac{v^2}{2s}[/tex]
[tex]\\ \tt\longmapsto a=\dfrac{62^2}{2(20.5)}[/tex]
[tex]\\ \tt\longmapsto a=\dfrac{3844}{41}[/tex]
[tex]\\ \tt\longmapsto a=93.7m/s^2[/tex]
Apply Newton's second law
[tex]\\ \tt\longmapsto F=ma[/tex]
[tex]\\ \tt\longmapsto F=44.9(93.7)[/tex]
[tex]\\ \tt\longmapsto F=4207.2N[/tex]
