Mercury lamps emit blue light with λ = 436 nm. What is the energy of these photons in joules?
Question 3 options:

a)

2.19 × 1018 J

b)

1.97 × 1044 J

c)

4.56 × 10−28 J

d)

4.56 × 10−19 J

e)

2.19 × 10−18 J
Pag

Substitute the values into the formula to have:
[tex]E=\frac{6.63 \times 10^{-34}\times 3.0 \times 10^8}{4.36 \times 10 ^ {-7}} \\E=4.56 \times 10^{-19} Joules[/tex]

Hence the energy of the photons is [tex]4.56 \times 10^{-19} Joules[/tex]

Learn more on energy of photons here; https://brainly.com/question/7464909

hamzaahmeds hamzaahmeds · Answer 2 · 2022-02-07T11:44:04+01:00

This question involves the concepts of Plank's Law.

The energy of the photons in Joules is "4.56 x 10⁻¹⁹ J".

PLANK'S LAW

According to Plank's Law, the energy of the photons is directly proportional to the frequency of those photons. Mathematically,

E = hν

where,

E = energy of photons = ?
h = Plank's constant = 6.625 x 10⁻³⁴ J.s
ν = frequency = [tex]\frac{c}{\lambda}[/tex]
c = speed of light = 3 x 10⁸ m/s
λ = wavelength = 436 nm = 4.36 x 10⁻⁷ m

Therefore,

[tex]E = h\nu = \frac{hc}{\lambda}\\\\E=\frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{4.36\ x\ 10^{-7}\ m}[/tex]

E = 4.56 x 10⁻¹⁹ J

Learn more about Plank's Law here:

https://brainly.com/question/24947800

Mercury lamps emit blue light with λ = 436 nm. What is the energy of these photons in joules? Question 3 options: a) 2.19 × 1018 J b) 1.97 × 1044 J c) 4.56 × 10−28 J d) 4.56 × 10−19 J e) 2.19 × 10−18 J Pag

Respuesta :

Energy of Photons

PLANK'S LAW

Otras preguntas

Mercury lamps emit blue light with λ = 436 nm. What is the energy of these photons in joules?
Question 3 options:

a)

2.19 × 1018 J

b)

1.97 × 1044 J

c)

4.56 × 10−28 J

d)

4.56 × 10−19 J

e)

2.19 × 10−18 J
Pag