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Let x be a positive number such that [tex]2x^2 = 4x + 9[/tex]. If x can be written in simplified form as [tex]$\dfrac{a + \sqrt{b}}{c}$[/tex] such that a, b, and c are positive integers, what is a + b + c?

Respuesta :

clarch19

Answer:

(4 ± 2[tex]\sqrt{22} [/tex]) ÷ 4

Step-by-step explanation:

i changed equation to be 2x² - 4x - 9 = 0

i used the quadratic formula:  (-b ± [tex]\sqrt{b^2-4ac} [/tex]) ÷ 2a

where:

a = 2

b = -4

c = -9

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