Statement:
A softball field is a square with sides of length 60 feet.
To find out:
The shortest distance between the first base and third base, i.e., the displacement
Solution:
- Let us consider 1st base as A, Home Plate as B and 3rd base as C.
- AB = 60 ft
- BC = 60 ft.
- To find out the shortest distance between the first base and third base we have to find out the value of AC.
- In right triangle ABC,
- (AB)² + (BC)² = (AC)² [By Pythagoras Theorem]
- or, (AC)² = (60 ft)² + (60 ft)²
- or, (AC)² = 3600 ft² + 3600 ft²
- or, (AC)² = 7200 ft²
- or, AC = √7200 ft
- So, the shortest distance will be √7200 ft.
Answer:
D. √7200 ft
Hope you could understand.
If you have any query, feel free to ask.
