contestada

To what power do you have to raise:
a) 3 to get 27?
to
b) 2 to get 32?
CO
c) 5 to get 625?
d) 64 to get 8?
e) 81 to get 3?
f) 64 to get 2?
g) x² to get x??
h) x to get x12?
10
i) x to get xa?

To what power do you have to raise a 3 to get 27 to b 2 to get 32 CO c 5 to get 625 d 64 to get 8 e 81 to get 3 f 64 to get 2 g x to get x h x to get x12 10 i x class=

Respuesta :

semsee45

Answer:

Step-by-step explanation:

a)  27 = 3 × 3 × 3 = 3³    Answer: 3

b)  32 = 2 × 2 × 2 × 2 × 2 = [tex]2^5[/tex]     Answer: 5

c) 625 = 5 × 5 × 5 × 5 = [tex]5^4[/tex]     Answer: 4

d) [tex]\sqrt{64} = 8 [/tex]  ⇒  [tex]64^{\frac{1}{2}} [/tex]    Answer: 1/2

e) [tex]\sqrt[4]{81}=3 [/tex]  ⇒  [tex]81^{\frac{1}{4}} [/tex]   Answer: 1/4

f) [tex]\sqrt[6]{64} =2[/tex]  ⇒  [tex]64^{\frac{1}{6} }[/tex]    Answer: 1/6

g) [tex](x^2)^{\frac{1}{2}}=x^1=x [/tex]     Answer: 1/2

h)  [tex](x^3)^{4}=x^{12}[/tex]    Answer: 4

i)  [tex](x)^8=x^8[/tex]   Answer: 8

devishri1977

Answer:

Step-by-step explanation:

Prime factorize 27,32,625,

a) 27 = 3 * 3 * 3 = 3³

b) 32 = 2 * 2 * 2 * 2 *2 = 2⁵

c) 625 = 5*5*5*5 = 5⁴

[tex]d) \sqrt{64}= (8^{2})^{\frac{1}{2}} = 8\\\\ e) \sqrt[4]{81}=\sqrt[4]{3*3*3*3}=(3^{4})^{\frac{1}{4}} = 3\\\\ f) \sqrt[6]{64}=\sqrt[6]{2*2*2*2*2*2}=(2^{6})^{\frac{1}{6}}=2\\\\ g)\sqrt{x^{2}}=(x^{2})^{\frac{1}{2}}=x\\\\ [/tex]

[tex]h) x^{12} = x^{3*4}= (x^{3})^{4}\\\\ i)x^{8}=x^{1*8}=(x^{1})^{8}[/tex]

Otras preguntas