I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT. Find the measure of one interior angle in the regular polygon.

Answer:
[tex]60 \textdegree [/tex]
Skills needed: Geometry
Step-by-step explanation:
1) We are given a regular triangle.
A regular triangle is the same as an equilateral triangle. This means that:
--> All sides are of equal length (congruent)
--> All angles are of same measure (congruent)
-------------------------------------------------------------------------------------------------------------Another thing to remember is that the sum of all angles in a triangle is 180 DEGREES.
------------------------------------------------------------------------------------------------------------- 2) Let's make an equation:
Let's make one of the angles a variable: [tex]y[/tex]
ALL the angles of the triangle will have a measure of "[tex]y[/tex]", which means that each of the angles equals [tex]y[/tex].
---> Sum of all angles (IN VARIABLE TERMS): [tex]y+y+y=3y[/tex] (1y+1y+1y = 3y)
ALSO:
- Sum of all angles is 180. This can be the right side of the equation.
[tex]3y = 180[/tex] is our equation based on all the information above.
We want to then isolate [tex]"y"[/tex], so we have to divide by 3.
[tex]3y \div 3=180 \div 3[/tex]
[tex]3y \div 3=y, 180 \div 3 = 60[/tex] (doing both division problems)
This means that: [tex]y=60[/tex]
60 should be the answer.