The school designed their garden to have a perimeter of 32 ft with the length measuring two feet more than twice the width

Based on the perimeter solved, the length and width of the rectangle will be 11.34 feet and 4.67 feet respectively.
Width = w
Length = 2w + 2
Perimeter = 2(Length + Width)
Perimeter = 2(Length + Width)
32 = 2(2w + 2 + w)
32 = 4w + 4 + 2w
32 - 4 = 6w
28 = 6w
w = 28/6 = 4.67
Length = 2w + 2 = (2 × 4.67) + 2 = 11.34
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