We are given –
- Mass of [tex] \bf CH_3OH[/tex] is 216.6 g and we are asked to find number of moles present in 216. 6 g of [tex] \bf CH_3OH[/tex]
[tex]\qquad[/tex][tex] \pink{\bf\longrightarrow { Molar \:mass \:of \: CH_3OH:-} }[/tex]
[tex]\qquad[/tex][tex] \bf \twoheadrightarrow 12+ 1\times 3 +16+1 [/tex]
[tex]\qquad[/tex][tex] \bf \twoheadrightarrow 32[/tex]
[tex]\qquad[/tex]____________________
Calculating the number of moles present in 216.6 g of [tex] \bf CH_3OH[/tex]
[tex]\qquad[/tex][tex] \purple{\sf\longrightarrow { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}[/tex]
[tex]\qquad[/tex][tex] \bf \twoheadrightarrow \dfrac{216.6}{32}[/tex]
[tex]\qquad[/tex][tex] \bf \twoheadrightarrow \cancel{\dfrac{216.6}{32}}[/tex]
[tex]\qquad[/tex][tex] \bf \twoheadrightarrow 6.768\: moles[/tex]
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