[tex] \qquad \quad \large {\pmb{ \frak { \mid {\overline{ \underline{\purple{ \bigstar \: Required \: Answer \: \bigstar}}}}}} \mid}\\[/tex]
We are given –
- Mass of C₁₂H₂₂O₁₁ is 179g. So, let's find molar mass and moles number of C₁₂H₂₂O₁₁.
[tex]\qquad[/tex][tex] \pink{\bf\longrightarrow { Molar \:mass \:of \:C₁₂H₂₂O₁₁ :-} }[/tex]
[tex]\qquad[/tex][tex] \bf \twoheadrightarrow 12\times 12+1\times 22+16\times 11 [/tex]
[tex]\qquad[/tex][tex] \bf \twoheadrightarrow 342[/tex]
[tex]\qquad[/tex]____________________
Calculating the number of moles present in 179 g of C₁₂H₂₂O₁₁.
[tex]\qquad[/tex][tex] \purple{\sf\longrightarrow { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}[/tex]
[tex]\qquad[/tex][tex] \bf \twoheadrightarrow \dfrac{179}{342}[/tex]
[tex]\qquad[/tex][tex] \bf \twoheadrightarrow \cancel{\dfrac{179}{342}}[/tex]
[tex]\qquad[/tex][tex]\purple{ \bf \twoheadrightarrow 0.523\: moles}[/tex]
- Avogadro number = 6.022×10²³
☀️No.Of Molecules –
=Moles × Avogadro number
= 0.523 × ( 6.02×10²³)
= 3.15 × 10²³
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