Answer:
Step-by-step explanation:
The following equation can be rewritten as:
[tex]9cos^2(\theta)-8sin(\theta)-8=0[/tex]
Then using trig identities (that sin^2 + cos^2 = 1) can be rewritten again as:
[tex]1-8\sin(\theta)-9\sin ^2(\theta)=0[/tex]
Which we can solve using quadratic formula to get that
sinθ = -1 and sinθ = 1/9
Which we can solve to get that:
θ = 3pi/2 + 2pi*n
and
θ = pi - 0.11134 + 2pi*n
where n is any positive integer
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