So, the value of work that he had done is 900 J.
Hi ! Here I will discuss about the effort to raise an object. Previously, when we raised an object, the energy that we put out had to be equal to the change in potential energyHi ! Here I will discuss about the effort to raise an object. Previously, when we raised an object, the energy that we put out had to be equal to the change in potential energy that happened. This is because, the higher the height of an object, the greater value of potential energy. The equation that applies is as follows :
[tex] \sf{\bold{W = \Delta PE}} [/tex]
[tex] \boxed{\sf{\bold{W = m \times g \times \Delta h}}} [/tex] ... (i)
[tex] \boxed{\sf{\bold{W = m \times g \times (h_2 - h_1)}}} [/tex] ... (ii)
With the following condition :
However, because the value of w (weight of the object) is already mass multiplied by gravity (w = m × g). So :
[tex] \sf{W = m \times g \times \Delta h} [/tex]
[tex] \boxed{\sf{\bold{W = w \times \Delta h)}}} [/tex]
With the following condition :
We know that :
What was asked :
Step by step :
[tex] \sf{W = w \times \Delta h} [/tex]
[tex] \sf{W = 600 \times 1.5} [/tex]
[tex] \boxed{\sf{W = 900 \: J}} [/tex]
So, the value of work that he had done is 900 J.
