contestada

A silver-colored necklace with a mass of 43.0 grams is heated in the drying oven to a temperature of
120.0ï‚°C. It is then dropped into a calorimeter containing 95.0 grams of water at 20.0ï‚°C. The water
and necklace reach a final temperature of 25.5ï‚°C. Determine, in Joules and in calories, how much
energy the water gained. Calculate the specific heat of the metal.

Respuesta :

mickymike92

Based on the data provided,  the heat gained by water is 2184.05 J and the heat capacity of silver is 0.537 J/g/°C

What is the heat gained by water?

Quantity of heat, H = mcΔT

where

  • m is mass
  • c is heat capacity
  • ΔT is temperature difference

Also;

  • Heat gained = heat lost

Heat capacity of water = 4.18 J/g/°C

Heat lost by silver = 43 * c * (120 - 25.5) = 4063.5c

Heat gained by water = 95 * 4.18 * (25.5 -20) = 2184.05 J

From heat lost = heat gained:

4063.5c = 2184.05 J

c = 2184.05/4063.5

c = 0.537 J/g/°C

Therefore, the heat gained by water is 2184.05 J and the heat capacity of silver is 0.537 J/g/°C

Learn more about heat capacity at: https://brainly.com/question/1105305

Otras preguntas