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A spring-loaded device with a spring constant of 4.0x10^3 newtons per meter is compressed a distance 0.25 meter when loaded. Calculate the maximum height to which this device will launch a 1.5 kilogram object.

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okpalawalter8

We have that the height is mathematically given as

  • h=8.5m

From the question we are told

  • A spring-loaded device with a spring constant of 4.0x10^3 newtons per meter is compressed a distance 0.25 meter when loaded.
  • Calculate the maximum height to which this device will launch a 1.5 kilogram object.

Height

Generally the equation for the Height  is mathematically given as

[tex]P.E=E_{sp}\\\\Where\\\\E=\frac{1}{2}*(4*110^3)(0.25)^2\\\\E_{sp}=125J\\\\Therefore\\\\mgh=125\\\\h=\frac{125}{1.5*9.8}[/tex]

  • h=8.5m

For more information on spring constant  visit

https://brainly.com/question/16517842

asuwafohjames

The maximum height to which the device will launch the object is 8.5 m.

The spring's elastic potential energy is equal to the potential energy of the object.

The maximum height of the object can be calculated using the formula below.

Formula:

  • ke²/2 = mgh............ Equation 1

Where:

  • e = compression of the spring
  • k = spring's constant
  • m = mass of the object
  • g = acceleration due to gravity
  • h =  maximum height at which the device will lunch the object.

Make h the subject of the equation

  • h = ke²/2mg............ Equation 2

From the question,

Given:

  • k = 4.0×10³ N/m
  • e = 0.25 m
  • m = 1.5 kg
  • g = 9.8 m/s²

Substitute these values into equation 2

  • h = 4000(0.25²)/(2×1.5×9.8)
  • h = 8.5 m.

Hence, The maximum height to which the device will launch the object is 8.5 m.

Learn more about maximum height here: https://brainly.com/question/6613758

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